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Class 7th Chapters
1. Integers 2. Fractions and Decimals 3. Data Handling
4. Simple Equations 5. Lines and Angles 6. The Triangle and its Properties
7. Congruence of Triangles 8. Comparing Quantities 9. Rational Numbers
10. Practical Geometry 11. Perimeter and Area 12. Algebraic Expressions
13. Exponents and Powers 14. Symmetry 15. Visualising Solid Shapes

Content On This Page
Integers & Their Addition and Subtraction Properties of Addition and Subtraction of Integers Multiplication of Integers
Division of Integers Order of Performing Operations


Chapter 1 Integers (Concepts)

Welcome to this foundational chapter which significantly expands our understanding of numbers! Building upon our knowledge of whole numbers from Class 6, we now encounter situations where whole numbers alone aren't enough. How do we represent temperatures below zero degrees, depths below sea level, or owing money? This chapter introduces the essential concept of Integers, a crucial set of numbers that includes all the familiar positive whole numbers ($1, 2, 3, \dots$), the negative whole numbers ($\dots, -3, -2, -1$), and the vital number zero ($0$). Mathematically, the set of integers is denoted by $Z = \{\dots, -3, -2, -1, 0, 1, 2, 3, \dots\}$. Understanding integers is fundamental for handling concepts of direction, opposites, gains, and losses, forming a critical base for future algebraic studies.

A key tool for visualizing and understanding integers is the number line. Imagine a straight line stretching infinitely in both directions with $0$ placed at the center. Positive integers ($1, 2, 3, \dots$) are marked at equal intervals to the right of zero, increasing in value as we move right. Negative integers ($-1, -2, -3, \dots$) are marked at equal intervals to the left of zero, decreasing in value as we move left. This visual representation makes comparing integers intuitive: any number on the right is always greater than any number on its left. Therefore, $2 > -1$, $0 > -3$, and importantly, $-2 > -5$. We also introduce the concept of absolute value, denoted by $|a|$, which represents the distance of an integer $a$ from zero on the number line, regardless of direction. Since distance is always non-negative, the absolute value is always positive or zero, for example, $|-7| = 7$ and $|+7| = 7$.

Mastering operations with integers is crucial. Adding integers can be visualized as movements on the number line: adding a positive integer means moving right, while adding a negative integer means moving left. Specific rules emerge: when adding integers with the same sign, we add their absolute values and keep the common sign (e.g., $5 + 3 = 8$, and $(-5) + (-3) = -8$). When adding integers with unlike signs, we subtract the smaller absolute value from the larger absolute value and assign the sign of the integer with the larger absolute value (e.g., $7 + (-4) = 3$, but $4 + (-7) = -3$). Subtraction is elegantly defined as adding the additive inverse (or opposite) of the number being subtracted. The additive inverse of $b$ is $-b$, and the additive inverse of $-b$ is $b$. Thus, $a - b$ is the same as $a + (-b)$, and $a - (-b)$ is the same as $a + b$. This definition allows us to convert any subtraction problem into an addition problem and apply the addition rules.

Multiplication and division of integers follow straightforward rules based on signs. The product or quotient of two integers with like signs (both positive or both negative) is always positive. For example, $6 \times 3 = 18$ and $(-6) \times (-3) = 18$. Conversely, the product or quotient of two integers with unlike signs (one positive and one negative) is always negative. For instance, $(-6) \times 3 = -18$ and $6 \times (-3) = -18$. These consistent rules simplify calculations involving multiplication and division.

Integers, like whole numbers, possess important properties under addition and multiplication that form the bedrock of algebra:

Understanding these properties allows for flexible and efficient computation. Practical applications abound, from tracking temperature changes and elevation differences to managing financial transactions (credits as positive, debits/withdrawals as negative, involving $\textsf{₹}$) and calculating scores in games with penalties. Mastering integer operations and properties is essential for success in algebra and beyond.



Integers & Their Addition and Subtraction

In earlier classes, you were introduced to the world of numbers, starting with natural numbers ($1, 2, 3, ...$) used for counting, and then expanding to whole numbers ($0, 1, 2, 3, ...$) by including zero. Now, we will broaden our number system even further to include a new set of numbers alongside whole numbers. This larger collection is called Integers. Integers are essential for representing quantities that can be opposite in direction or value, such as temperatures above and below zero, or gaining and losing money.


What are Integers?

Integers are a collection of numbers that includes all whole numbers ($0, 1, 2, 3, ...$) and the negative counterparts of the natural numbers ($-1, -2, -3, ...$). This means integers can be positive, negative, or zero.

The set of integers can be represented as: $\{..., -5, -4, -3, -2, -1, 0, 1, 2, 3, 4, 5, ...\}$.

Integers are denoted by the symbol $\mathbb{Z}$ (or sometimes $I$). The symbol $\mathbb{Z}$ comes from the German word 'Zahlen', which means 'numbers'.

Based on their value relative to zero, integers are classified into three groups:

All natural numbers are positive integers. All whole numbers are integers. However, not all integers are whole numbers (e.g., $-7$ is an integer but not a whole number), and not all integers are natural numbers (e.g., $0$ and $-7$ are integers but not natural numbers).


Representation of Integers on a Number Line

The number line is a valuable tool for visualising and comparing integers. It helps us understand the order and relative values of integers.

To represent integers on a number line, follow these steps:

  1. Draw a straight line and extend it infinitely in both directions (indicated by arrows at the ends).
  2. Mark a point near the center of the line and label it as $0$. This is the origin.
  3. Mark points to the right of $0$ at equal distances. Label these points $1, 2, 3, 4, ...$ in increasing order. These represent the positive integers. The direction to the right of $0$ is the positive direction.
  4. Mark points to the left of $0$ at the same equal distances as used on the right. Label these points $-1, -2, -3, -4, ...$ in decreasing order. These represent the negative integers. The direction to the left of $0$ is the negative direction.
Number line showing positive integers to the right of zero, and negative integers to the left of zero.

From the number line, we can make the following observations about comparing integers:


Absolute Value of an Integer

The Absolute Value of an integer is its numerical value without considering whether it is positive or negative. It represents the distance of the integer from zero on the number line. Since distance is always measured as a non-negative quantity (you can't walk a negative distance), the absolute value of any integer is always non-negative (zero or a positive number).

The absolute value of an integer 'a' is denoted by writing the integer within two vertical bars, like this: $|a|$.

For example:

We can define the absolute value using a piecewise function:

$|a| = \begin{cases} a & , & \text{if } a \text{ is zero or positive } (a \ge 0) \\ -a & , & \text{if } a \text{ is negative } (a < 0) \end{cases}$

When $a$ is negative, $-a$ represents the additive inverse of $a$, which is its positive counterpart. For instance, if $a = -8$, then $|a| = |-8| = -(-8) = 8$.


Addition of Integers

Adding integers involves combining quantities that might be positive (moving right on the number line) or negative (moving left on the number line). We can formulate rules for addition based on the signs of the integers being added.

Rule 1: Adding two positive integers

When adding two positive integers, the sum is always a positive integer. Simply add their absolute values (which are the numbers themselves) and the result is positive.

$(+\text{a}) + (+\text{b}) = +(\text{a} + \text{b})$ or $a + b$.

Example: $(+5) + (+3) = 5 + 3 = 8$. (On number line: Start at 5, move 3 units right $\to$ 8)

Example: $10 + 15 = 25$.

Rule 2: Adding two negative integers

When adding two negative integers, the sum is always a negative integer. Add their absolute values and place a negative sign before the sum.

$(-\text{a}) + (-\text{b}) = -(\text{a} + \text{b})$.

Example: $(-5) + (-3)$. Absolute values are $|-5|=5$ and $|-3|=3$. Sum of absolute values is $5+3=8$. Place a negative sign: $-8$.

$(-5) + (-3) = -(5+3) = -8$

(On number line: Start at -5, move 3 units left $\to$ -8)

Example: $(-10) + (-15) = -(10+15) = -25$.

Rule 3: Adding one positive and one negative integer

When adding a positive integer and a negative integer, the sign of the sum depends on which integer has the larger absolute value. To find the sum, find the difference between their absolute values. The sum takes the sign of the integer with the greater absolute value.

$(+\text{a}) + (-\text{b})$ or $(-\text{a}) + (+\text{b})$

Result is $(|a| - |b|)$ or $(|b| - |a|)$ with the sign of the integer having the greater absolute value.

Example 1: $(+7) + (-3)$. Absolute values are $|+7|=7$ and $|-3|=3$. Difference $7-3=4$. Integer with larger absolute value is $+7$ (positive). Sum is $+4$ or $4$.

$(+7) + (-3) = +(7-3) = +4$

(On number line: Start at 7, move 3 units left $\to$ 4)

Example 2: $(-7) + (+3)$. Absolute values are $|-7|=7$ and $|+3|=3$. Difference $7-3=4$. Integer with larger absolute value is $-7$ (negative). Sum is $-4$.

$(-7) + (+3) = -(7-3) = -4$

(On number line: Start at -7, move 3 units right $\to$ -4)

Example 3: $(+4) + (-4)$. Absolute values are $|+4|=4$ and $|-4|=4$. Difference $4-4=0$. The sum is $0$. (+4 and -4 are additive inverses, their sum is always 0).

$(+4) + (-4) = 0$

Example 4: $(-10) + (+12)$. Absolute values $|-10|=10, |+12|=12$. Difference $12-10=2$. Sign of $+12$ (positive). Sum is $+2$ or $2$.

Example 5: $(+10) + (-12)$. Absolute values $|+10|=10, |-12|=12$. Difference $12-10=2$. Sign of $-12$ (negative). Sum is $-2$.


Subtraction of Integers

Subtraction of integers is defined in terms of addition. Subtracting an integer is the same as adding its additive inverse (opposite).

The Additive Inverse of an integer 'a' is the integer that, when added to 'a', gives zero. The additive inverse of 'a' is denoted by '-a'.

Rule for Subtraction: To subtract an integer 'b' from an integer 'a', add the additive inverse of 'b' to 'a'.

$a - b = a + (\text{additive inverse of } b)$

Since the additive inverse of $b$ is $-b$, the rule is $a - b = a + (-b)$.

Since the additive inverse of $-b$ is $b$, the rule for subtracting a negative is $a - (-b) = a + (\text{additive inverse of } -b) = a + b$.

Examples of Subtraction:

1. Subtract $(+3)$ from $(+5)$. This is written as $(+5) - (+3)$.

$(+5) - (+3) = (+5) + (\text{additive inverse of } +3)$

$= (+5) + (-3)$

Now, use the addition rule for $(+\text{a}) + (-\text{b})$: $|+5|=5, |-3|=3$. Difference $5-3=2$. Sign is positive (from +5). Result is 2.

So, $(+5) - (+3) = 2$.

2. Subtract $(-3)$ from $(+5)$. This is written as $(+5) - (-3)$.

$(+5) - (-3) = (+5) + (\text{additive inverse of } -3)$

$= (+5) + (+3)$

Now, use the addition rule for two positive integers: $5+3=8$. Result is 8.

So, $(+5) - (-3) = 8$.

3. Subtract $(+3)$ from $(-5)$. This is written as $(-5) - (+3)$.

$(-5) - (+3) = (-5) + (\text{additive inverse of } +3)$

$= (-5) + (-3)$

Now, use the addition rule for two negative integers: $-(5+3)=-8$. Result is -8.

So, $(-5) - (+3) = -8$.

4. Subtract $(-3)$ from $(-5)$. This is written as $(-5) - (-3)$.

$(-5) - (-3) = (-5) + (\text{additive inverse of } -3)$

$= (-5) + (+3)$

Now, use the addition rule for $(-\text{a}) + (+\text{b})$: $|-5|=5, |+3|=3$. Difference $5-3=2$. Sign is negative (from -5). Result is -2.

So, $(-5) - (-3) = -2$.


Addition and Subtraction of Integers on a Number Line

The number line provides a visual way to perform addition and subtraction of integers. The basic rules of movement are:

Since subtraction is defined as adding the opposite, the rules for subtraction are:

Examples of Addition on the Number Line

(a) Find $2 + 3$:

Start at $2$. Since we are adding a positive integer ($3$), move $3$ units to the right. We land on $5$. So, $2 + 3 = 5$.

Number line showing addition of 2 and 3. Start at 2 and move 3 steps right to reach 5.

(b) Find $(-2) + (-3)$:

Start at $-2$. Since we are adding a negative integer ($-3$), move $3$ units to the left. We land on $-5$. So, $(-2) + (-3) = -5$.

Number line showing addition of -2 and -3. Start at -2 and move 3 steps left to reach -5.

(c) Find $5 + (-3)$:

Start at $5$. Since we are adding a negative integer ($-3$), move $3$ units to the left. We land on $2$. So, $5 + (-3) = 2$.

Number line showing addition of 5 and -3. Start at 5 and move 3 steps left to reach 2.

Examples of Subtraction on the Number Line

(a) Find $4 - 6$:

This is the same as $4 + (-6)$. Start at $4$. Move $6$ units to the left. We land on $-2$. So, $4 - 6 = -2$.

Number line showing subtraction of 6 from 4. Start at 4 and move 6 steps left to reach -2.

(b) Find $3 - (-4)$:

This is the same as $3 + 4$. Start at $3$. Move $4$ units to the right. We land on $7$. So, $3 - (-4) = 7$.

Number line showing subtraction of -4 from 3. Start at 3 and move 4 steps right to reach 7.

Example 1. Find the sum: (a) $(-7) + (-9)$ (b) $(+23) + (-15)$

Answer:

(a) Find the sum of $(-7) + (-9)$.

We are adding two negative integers. According to Rule 2 for addition, we add their absolute values and place a negative sign before the result.

Absolute value of $-7$ is $|-7| = 7$.

Absolute value of $-9$ is $|-9| = 9$.

Sum of absolute values $= 7 + 9 = 16$.

Place a negative sign before the sum: $-16$.

Therefore, $(-7) + (-9) = -16$.


(b) Find the sum of $(+23) + (-15)$.

We are adding a positive integer ($+23$) and a negative integer ($-15$). According to Rule 3 for addition, we find the difference between their absolute values and give the sum the sign of the integer with the larger absolute value.

Absolute value of $+23$ is $|+23| = 23$.

Absolute value of $-15$ is $|-15| = 15$.

Difference between absolute values $= 23 - 15 = 8$.

Compare absolute values: $23 > 15$. The integer with the larger absolute value is $+23$, which is positive. So the sum will be positive.

Therefore, $(+23) + (-15) = +8$ or simply $8$.

Example 2. Subtract: (a) $(-6)$ from $(4)$ (b) $(-12)$ from $(-8)$

Answer:

(a) Subtract $(-6)$ from $(4)$. This means we calculate $(4) - (-6)$.

Using the subtraction rule, $a - b = a + (-b)$, we convert the subtraction to adding the additive inverse.

$(4) - (-6) = (4) + (\text{additive inverse of } -6)$

The additive inverse of $-6$ is $+6$ (or 6).

$= (4) + (+6)$

Now, we add two positive integers: $4 + 6 = 10$.

So, $(4) - (-6) = 10$.


(b) Subtract $(-12)$ from $(-8)$. This means we calculate $(-8) - (-12)$.

Using the subtraction rule, $a - b = a + (-b)$, convert to adding the additive inverse.

$(-8) - (-12) = (-8) + (\text{additive inverse of } -12)$

The additive inverse of $-12$ is $+12$ (or 12).

$= (-8) + (+12)$

Now, we add a negative integer ($-8$) and a positive integer ($+12$). Use Rule 3 for addition: find the difference between absolute values and use the sign of the integer with larger absolute value.

Absolute value of $-8$ is $|-8| = 8$.

Absolute value of $+12$ is $|+12| = 12$.

Difference: $12 - 8 = 4$.

Compare absolute values: $12 > 8$. The integer with the larger absolute value is $+12$, which is positive. So the sum is positive.

Therefore, $(-8) + (+12) = +4$ or $4$.

So, $(-8) - (-12) = 4$.



Properties of Addition and Subtraction of Integers

When we work with numbers, understanding their properties helps us perform calculations more efficiently and provides a deeper insight into how they behave. Integers, as an extended set of numbers, also follow certain properties under the operations of addition and subtraction. Let's explore these important properties.


1. Closure Property

The closure property states that when you perform an operation on two numbers from a set, the result is also a number belonging to the same set.

(a) Closure under Addition

The set of integers is closed under addition. This means that if you add any two integers, the sum you get will always be another integer.

In mathematical terms: If '$a$' and '$b$' are any two integers, then their sum, $a + b$, is also an integer.

Let's look at some examples:

In every case, adding two integers results in an integer. So, the set of integers is closed under addition.

(b) Closure under Subtraction

The set of integers is also closed under subtraction. This means that if you subtract one integer from another integer, the difference you get will always be an integer.

In mathematical terms: If '$a$' and '$b$' are any two integers, then their difference, $a - b$, is also an integer.

Let's look at some examples:

In every case, subtracting one integer from another results in an integer. So, the set of integers is closed under subtraction.


2. Commutative Property

The commutative property deals with whether the order of the numbers matters in an operation.

(a) Commutativity of Addition

Addition of integers is commutative. This means that when you add two integers, changing the order in which you add them does not change the sum.

In mathematical terms: If '$a$' and '$b$' are any two integers, then $a + b = b + a$.

Let's verify this with an example:

Let $a = 5$ and $b = -3$.

Calculate $a + b$:

$a + b = 5 + (-3)$

Using the rule for adding a positive and negative integer ($|5|=5, |-3|=3$, difference $5-3=2$, sign of 5 is positive):

$5 + (-3) = 2$

Calculate $b + a$:

$b + a = (-3) + 5$

Using the rule for adding a negative and positive integer ($|-3|=3, |5|=5$, difference $5-3=2$, sign of 5 is positive):

$(-3) + 5 = 2$

Since both $a+b$ and $b+a$ give the same result (2), the commutative property holds for addition of integers: $5 + (-3) = (-3) + 5$.

(b) Subtraction is NOT Commutative for Integers

Subtraction of integers is not commutative. This means that if you change the order of the integers in a subtraction, the result generally changes (unless the two integers are equal).

In mathematical terms: If '$a$' and '$b$' are any two distinct integers ($a \neq b$), then $a - b \neq b - a$.

Let's verify this with an example:

Let $a = 5$ and $b = -3$.

Calculate $a - b$:

$a - b = 5 - (-3)$

Using the subtraction rule ($a - (-b) = a + b$):

$5 - (-3) = 5 + 3 = 8$

Calculate $b - a$:

$b - a = (-3) - 5$

Using the subtraction rule ($a - b = a + (-b)$):

$(-3) - 5 = (-3) + (-5)$

Using the rule for adding two negative integers (add absolute values and make negative):

$(-3) + (-5) = -(3+5) = -8$

Since $8 \neq -8$, the commutative property does not hold for subtraction of integers: $5 - (-3) \neq (-3) - 5$.


3. Associative Property

The associative property deals with how grouping affects the result when performing an operation on three or more numbers.

(a) Associativity of Addition

Addition of integers is associative. This means that when adding three or more integers, the way you group them using parentheses does not affect the final sum.

In mathematical terms: If '$a$', '$b$', and '$c$' are any three integers, then $(a + b) + c = a + (b + c)$.

Let's verify this with an example:

Let $a = -5$, $b = 3$, and $c = -2$.

Calculate the Left Hand Side (LHS): $(a + b) + c$

$(a + b) + c = ((-5) + 3) + (-2)$

First, calculate the sum inside the first parenthesis: $(-5) + 3$. (Rule 3: $|-5|=5, |3|=3$, difference 2, sign of -5). $(-5)+3 = -2$.

Now, add the result to $c$: $(-2) + (-2)$. (Rule 2: add absolute values and make negative). $-(2+2) = -4$.

So, LHS $= -4$.

Calculate the Right Hand Side (RHS): $a + (b + c)$

$a + (b + c) = (-5) + (3 + (-2))$

First, calculate the sum inside the parenthesis: $3 + (-2)$. (Rule 3: $|3|=3, |-2|=2$, difference 1, sign of 3). $3+(-2) = 1$.

Now, add $a$ to the result: $(-5) + 1$. (Rule 3: $|-5|=5, |1|=1$, difference 4, sign of -5). $(-5)+1 = -4$.

So, RHS $= -4$.

Since LHS = RHS (both are -4), the associative property holds for addition of integers: $(a + b) + c = a + (b + c)$.

(b) Subtraction is NOT Associative for Integers

Subtraction of integers is not associative. This means that the way you group integers when performing multiple subtractions affects the result.

In mathematical terms: If '$a$', '$b$', and '$c$' are any three integers, then $(a - b) - c \neq a - (b - c)$ (except for some specific cases where the equality might accidentally hold).

Let's verify this with an example:

Let $a = 8$, $b = 4$, and $c = 2$.

Calculate the Left Hand Side (LHS): $(a - b) - c$

$(a - b) - c = (8 - 4) - 2$

First, calculate inside the parenthesis: $8 - 4 = 4$.

Now, subtract $c$: $4 - 2 = 2$.

So, LHS $= 2$.

Calculate the Right Hand Side (RHS): $a - (b - c)$

$a - (b - c) = 8 - (4 - 2)$

First, calculate inside the parenthesis: $4 - 2 = 2$.

Now, subtract this result from $a$: $8 - 2 = 6$.

So, RHS $= 6$.

Since LHS ($2$) is not equal to RHS ($6$), $(a - b) - c \neq a - (b - c)$. The associative property does not hold for subtraction of integers.


4. Additive Identity

The Additive Identity is a special number that, when added to any number, does not change the value of that number. For integers, the additive identity is zero.

Zero ($0$) is the additive identity for integers. This means that adding $0$ to any integer leaves the integer unchanged.

In mathematical terms: If '$a$' is any integer, then $a + 0 = 0 + a = a$.

Examples:


5. Additive Inverse

For every integer, there exists another integer called its additive inverse. The Additive Inverse of an integer is the number which, when added to the integer, gives the additive identity (0) as the sum.

In mathematical terms: For every integer '$a$', there exists an integer '$-a$' such that $a + (-a) = (-a) + a = 0$. The integer '$-a$' is called the additive inverse of '$a$'.

The concept of additive inverse is fundamental to understanding subtraction of integers, as we saw earlier: $a - b = a + (-b)$. Subtracting an integer is equivalent to adding its additive inverse.


Example 1. Write down a pair of integers whose: (a) sum is -7 (b) difference is -10 (c) sum is 0.

Answer:

(a) We need a pair of integers that add up to -7. There are infinitely many such pairs. Some examples:

  • If we add two negative integers: $(-3) + (-4) = -7$. So, the pair $(-3, -4)$ works.
  • If we add a negative and a positive integer: $(-10) + 3 = -7$. So, the pair $(-10, 3)$ works.
  • Another pair of negative integers: $(-5) + (-2) = -7$. So, the pair $(-5, -2)$ works.
  • If we start with a positive integer, say 5, what should we add to get -7? $5 + \text{?} = -7$. The answer is $-12$. $5 + (-12) = -7$. So, the pair $(5, -12)$ works.

One such pair of integers whose sum is -7 is (-3, -4).

(b) We need a pair of integers whose difference is -10. This means $a - b = -10$. Again, there are many possible pairs. Some examples:

  • Let $a = -20$. Then $-20 - b = -10$. Adding $b$ to both sides: $-20 = -10 + b$. Adding 10 to both sides: $-20 + 10 = b$, so $b = -10$. The pair is (-20, -10), since $(-20) - (-10) = -20 + 10 = -10$.
  • Let $a = 5$. Then $5 - b = -10$. Add $b$ to both sides: $5 = -10 + b$. Add 10 to both sides: $5 + 10 = b$, so $b=15$. The pair is (5, 15), since $5 - 15 = 5 + (-15) = -10$.
  • Let $a = -5$. Then $-5 - b = -10$. Add $b$ to both sides: $-5 = -10 + b$. Add 10 to both sides: $-5 + 10 = b$, so $b=5$. The pair is (-5, 5), since $(-5) - 5 = (-5) + (-5) = -10$.

One such pair of integers whose difference is -10 is (5, 15).

(c) We need a pair of integers whose sum is 0. As we learned, the sum of an integer and its additive inverse is 0. So, any integer and its opposite form such a pair.

  • If one integer is -5, its additive inverse is 5. $(-5) + 5 = 0$. The pair is (-5, 5).
  • If one integer is 12, its additive inverse is -12. $(12) + (-12) = 0$. The pair is (12, -12).
  • If one integer is 0, its additive inverse is 0. $0 + 0 = 0$. The pair is (0, 0).

One such pair of integers whose sum is 0 is (12, -12).

Example 2. Verify the property $a - (-b) = a + b$ for the given values $a = 21$ and $b = 18$.

Answer:

Given property to verify: $a - (-b) = a + b$.

Given values: $a = 21$ and $b = 18$.

We need to substitute the given values into both the LHS and RHS of the property and check if they are equal.

Evaluate LHS (Left Hand Side):

The LHS of the property is $a - (-b)$.

Substitute $a=21$ and $b=18$ into the LHS expression:

LHS $= 21 - (-(18))$

We know that $-(-b) = +b$, so $-(-18) = +18$ or $18$.

LHS $= 21 - (-18) = 21 + 18$

Perform the addition of the two positive integers:

$21 + 18 = 39$

So, LHS $= 39$.

Evaluate RHS (Right Hand Side):

The RHS of the property is $a + b$.

Substitute $a=21$ and $b=18$ into the RHS expression:

RHS $= 21 + 18$

Perform the addition of the two positive integers:

$21 + 18 = 39$

So, RHS $= 39$.

Compare the values of LHS and RHS:

LHS $= 39$

RHS $= 39$

Since LHS = RHS ($39 = 39$), the property $a - (-b) = a + b$ is indeed verified for the given values of $a=21$ and $b=18$. This demonstrates the rule that subtracting a negative integer is the same as adding the corresponding positive integer.



Multiplication of Integers

We have learned how to add and subtract integers, including understanding their properties. Now, we will explore the operation of Multiplication of Integers. Just as multiplication of whole numbers is repeated addition (e.g., $3 \times 4$ means adding 3 groups of 4, or $4+4+4$), multiplication of integers also relates to repeated addition, but we must consider the signs of the numbers.


Rules for Multiplication of Integers

The sign of the product of two integers depends on the signs of the integers being multiplied. Here are the rules:

1. Multiplication of two positive integers

The product of two positive integers is always a positive integer. This is the same as multiplying natural numbers or whole numbers.

$ (+\text{a}) \times (+\text{b}) = +(\text{a} \times \text{b}) $

Or simply: Positive $\times$ Positive $=$ Positive

Example: $(+4) \times (+5) = 4 \times 5 = 20$.

Example: $10 \times 6 = 60$.

2. Multiplication of two negative integers

The product of two negative integers is always a positive integer. To find the product, multiply their absolute values.

$ (-\text{a}) \times (-\text{b}) = +(\text{a} \times \text{b}) $

Or simply: Negative $\times$ Negative $=$ Positive

Example: $(-4) \times (-5)$.

Multiply the absolute values: $|-4| \times |-5| = 4 \times 5 = 20$.

Since both integers are negative, the product is positive.

So, $(-4) \times (-5) = 20$.

Example: $(-10) \times (-3) = +(10 \times 3) = 30$.

3. Multiplication of one positive and one negative integer

The product of a positive integer and a negative integer (in any order) is always a negative integer. To find the product, multiply their absolute values and place a negative sign before the result.

$ (+\text{a}) \times (-\text{b}) = -(\text{a} \times \text{b}) $

$ (-\text{a}) \times (+\text{b}) = -(\text{a} \times \text{b}) $

Or simply: Positive $\times$ Negative $=$ Negative, and Negative $\times$ Positive $=$ Negative.

Example 1: $(+4) \times (-5)$.

Multiply the absolute values: $|+4| \times |-5| = 4 \times 5 = 20$.

Since one integer is positive and the other is negative, the product is negative.

So, $(+4) \times (-5) = -20$.

Example 2: $(-4) \times (+5)$.

Multiply the absolute values: $|-4| \times |+5| = 4 \times 5 = 20$.

Since one integer is negative and the other is positive, the product is negative.

So, $(-4) \times (+5) = -20$.

Example 3: $7 \times (-9) = -(7 \times 9) = -63$.

Example 4: $(-11) \times 2 = -(11 \times 2) = -22$.

Summary of Sign Rules for Multiplication:

The sign rules for multiplication can be summarised concisely:

First Integer Sign Second Integer Sign Product Sign
Positive (+) Positive (+) Positive (+)
Negative (-) Negative (-) Positive (+)
Positive (+) Negative (-) Negative (-)
Negative (-) Positive (+) Negative (-)

A simpler way to remember the sign rules: If the two integers have the **same sign**, the product is **positive**. If the two integers have **different signs**, the product is **negative**.


Properties of Multiplication of Integers

Multiplication of integers follows several important properties, similar to addition, that are helpful for understanding and manipulating integer expressions.

1. Closure under Multiplication

The set of integers is closed under multiplication. This means that the product of any two integers is always an integer.

If '$a$' and '$b$' are any two integers, then their product, $a \times b$, is also an integer.

Examples:

The closure property ensures that when you multiply any two integers, you will always get a result that is still within the set of integers.

2. Commutativity of Multiplication

Multiplication of integers is commutative. This means that the order in which you multiply two integers does not change the product.

In mathematical terms: If '$a$' and '$b$' are any two integers, then $a \times b = b \times a$.

Let's verify this with an example involving negative integers:

Let $a = -4$ and $b = 7$.

Calculate $a \times b$:

$a \times b = (-4) \times 7$

Using the rule for multiplying a negative and a positive integer:

$(-4) \times 7 = -(4 \times 7) = -28$.

Calculate $b \times a$:

$b \times a = 7 \times (-4)$

Using the rule for multiplying a positive and a negative integer:

$7 \times (-4) = -(7 \times 4) = -28$.

Since both $a \times b$ and $b \times a$ give the same result (-28), the commutative property holds for multiplication of integers: $(-4) \times 7 = 7 \times (-4)$.

3. Associativity of Multiplication

Multiplication of integers is associative. This property applies when multiplying three or more integers. It states that the way you group the integers using parentheses does not affect the final product.

In mathematical terms: If '$a$', '$b'$, and '$c$' are any three integers, then $(a \times b) \times c = a \times (b \times c)$.

Let's verify this with an example:

Let $a = -2$, $b = 3$, and $c = -4$.

Calculate the Left Hand Side (LHS): $(a \times b) \times c$

$(a \times b) \times c = ((-2) \times 3) \times (-4)$

First, calculate inside the first parenthesis: $(-2) \times 3$. (Negative $\times$ Positive $=$ Negative). $(-2) \times 3 = -6$.

Now, multiply the result by $c$: $(-6) \times (-4)$. (Negative $\times$ Negative $=$ Positive). $(-6) \times (-4) = +(6 \times 4) = 24$.

So, LHS $= 24$.

Calculate the Right Hand Side (RHS): $a \times (b \times c)$

$a \times (b \times c) = (-2) \times (3 \times (-4))$

First, calculate inside the parenthesis: $3 \times (-4)$. (Positive $\times$ Negative $=$ Negative). $3 \times (-4) = -(3 \times 4) = -12$.

Now, multiply $a$ by the result: $(-2) \times (-12)$. (Negative $\times$ Negative $=$ Positive). $(-2) \times (-12) = +(2 \times 12) = 24$.

So, RHS $= 24$.

Since LHS = RHS (both are 24), the associative property holds for multiplication of integers: $(a \times b) \times c = a \times (b \times c)$. This property allows us to multiply three or more integers by grouping any two first.

4. Multiplicative Identity

The Multiplicative Identity is a special number that, when multiplied by any number, results in the number itself. For integers, the multiplicative identity is one.

One ($1$) is the multiplicative identity for integers. Multiplying any integer by $1$ does not change its value.

In mathematical terms: If '$a$' is any integer, then $a \times 1 = 1 \times a = a$.

Examples:

Note: Multiplying an integer by $-1$ gives its additive inverse. If '$a$' is any integer, $a \times (-1) = (-1) \times a = -a$.

Example: $5 \times (-1) = -5$. The additive inverse of 5 is -5.

Example: $(-8) \times (-1) = 8$. The additive inverse of -8 is 8.

5. Property of Zero in Multiplication

The property of zero in multiplication of integers is the same as for whole numbers.

Rule: The product of any integer and zero ($0$) is always zero ($0$).

In mathematical terms: If '$a$' is any integer, then $a \times 0 = 0 \times a = 0$.

Examples:

6. Distributive Property of Multiplication over Addition

This property links the operations of multiplication and addition. It states that multiplying an integer by a sum of two other integers is the same as multiplying the integer by each of the other integers separately and then adding the products.

In mathematical terms: If '$a$', '$b$', and '$c$' are any three integers, then $a \times (b + c) = (a \times b) + (a \times c)$.

This property is extremely useful for simplifying calculations or rewriting expressions.

Let's verify this with an example:

Let $a = -3$, $b = 4$, and $c = -2$.

Calculate the Left Hand Side (LHS): $a \times (b + c)$

$a \times (b + c) = (-3) \times (4 + (-2))$

First, calculate the sum inside the parenthesis: $4 + (-2)$. (Rule 3 for addition: $|4|=4, |-2|=2$, difference 2, sign of 4). $4 + (-2) = 2$.

Now, multiply $a$ by the sum: $(-3) \times (2)$. (Rule 3 for multiplication: Negative $\times$ Positive $=$ Negative). $(-3) \times 2 = -6$.

So, LHS $= -6$.

Calculate the Right Hand Side (RHS): $(a \times b) + (a \times c)$

$(a \times b) + (a \times c) = ((-3) \times 4) + ((-3) \times (-2))$

First product: $(-3) \times 4$. (Negative $\times$ Positive $=$ Negative). $(-3) \times 4 = -12$.

Second product: $(-3) \times (-2)$. (Negative $\times$ Negative $=$ Positive). $(-3) \times (-2) = +6$.

Now, add the two products: $(-12) + (6)$. (Rule 3 for addition: $|-12|=12, |6|=6$, difference 6, sign of -12). $(-12) + 6 = -6$.

So, RHS $= -6$.

Since LHS = RHS (both are -6), the distributive property of multiplication over addition holds for integers: $a \times (b + c) = (a \times b) + (a \times c)$.

7. Distributive Property of Multiplication over Subtraction

Multiplication of integers also distributes over their subtraction.

In mathematical terms: If '$a$', '$b'$, and '$c$' are any three integers, then $a \times (b - c) = (a \times b) - (a \times c)$.

Let's verify this with an example:

Let $a = 5$, $b = 7$, and $c = 3$.

Calculate the Left Hand Side (LHS): $a \times (b - c)$

$a \times (b - c) = 5 \times (7 - 3)$

First, calculate the difference inside the parenthesis: $7 - 3 = 4$.

Now, multiply $a$ by the difference: $5 \times 4 = 20$.

So, LHS $= 20$.

Calculate the Right Hand Side (RHS): $(a \times b) - (a \times c)$

$(a \times b) - (a \times c) = (5 \times 7) - (5 \times 3)$

First product: $5 \times 7 = 35$.

Second product: $5 \times 3 = 15$.

Now, subtract the second product from the first: $35 - 15 = 20$.

So, RHS $= 20$.

Since LHS = RHS (both are 20), the distributive property of multiplication over subtraction holds for integers: $a \times (b - c) = (a \times b) - (a \times c)$.


Multiplication of Three or More Negative Integers

When you multiply more than two integers, you can extend the sign rules. If there are multiple negative signs, the sign of the final product depends on whether the number of negative signs is even or odd.

Examples:

1. $(-2) \times (-3) \times (-4)$

There are three negative integers in the product (3 is an odd number). So the final product will be negative.

Let's calculate step-by-step: First multiply $(-2) \times (-3) = +(2 \times 3) = 6$.

Now multiply the result by $(-4)$: $6 \times (-4) = -(6 \times 4) = -24$.

So, $(-2) \times (-3) \times (-4) = -24$.

2. $(-2) \times (-3) \times (-4) \times (-1)$

There are four negative integers in the product (4 is an even number). So the final product will be positive.

Calculate step-by-step (or group): $(-2) \times (-3) = 6$.

$(-4) \times (-1) = +(4 \times 1) = 4$.

Now multiply the results: $6 \times 4 = 24$.

So, $(-2) \times (-3) \times (-4) \times (-1) = 24$.


Example 1. Find the product using suitable properties: (a) $26 \times (-48) + (-48) \times (-36)$ (b) $8 \times 53 \times (-125)$

Answer:

(a) We need to evaluate $26 \times (-48) + (-48) \times (-36)$.

Observe that $(-48)$ is common in both terms ($26 \times (-48)$ and $(-48) \times (-36)$). This suggests using the distributive property $a \times c + b \times c = (a+b) \times c$ or $c \times a + c \times b = c \times (a+b)$.

Let $a=26$, $b=-36$, and $c=-48$. The expression is in the form $a \times c + b \times c$.

$26 \times (-48) + (-36) \times (-48)$

(Rearranging terms using commutativity)

$ = (26 + (-36)) \times (-48) $

(Using distributive property $(a+b) \times c = a \times c + b \times c$)

Calculate the sum inside the parenthesis: $26 + (-36)$. (Rule 3 for addition: $|26|=26, |-36|=36$, difference $36-26=10$, sign of -36). $26 + (-36) = -10$.

Now, multiply the result by -48:

$ = (-10) \times (-48) $

Multiply the two negative integers. (Rule 2 for multiplication: Negative $\times$ Negative $=$ Positive). $|-10|=10, |-48|=48$. $10 \times 48 = 480$.

$ = 480 $

So, $26 \times (-48) + (-48) \times (-36) = 480$.


(b) We need to evaluate $8 \times 53 \times (-125)$.

When multiplying three or more numbers, the associative and commutative properties allow us to group and reorder the numbers for easier calculation. Notice that multiplying 8 and 125 gives a simple number (1000). Let's group 8 and -125 together.

$8 \times 53 \times (-125) = 53 \times (8 \times (-125)) $

(Using commutative and associative properties to group 8 and -125)

First, calculate the product inside the parenthesis: $8 \times (-125)$. (Rule 3 for multiplication: Positive $\times$ Negative $=$ Negative). $8 \times (-125) = -(8 \times 125)$.

Calculate $8 \times 125$. You can do this step-by-step: $8 \times 100 = 800$, $8 \times 25 = 200$. $800 + 200 = 1000$.

So, $8 \times (-125) = -1000$.

Now, multiply the remaining numbers:

$ = 53 \times (-1000) $

Multiply a positive integer by $-1000$. (Rule 3 for multiplication: Positive $\times$ Negative $=$ Negative). $53 \times (-1000) = -(53 \times 1000) = -53000$.

$ = -53000 $

Therefore, $8 \times 53 \times (-125) = -53000$. Using properties made the multiplication much simpler.



Division of Integers

We have explored addition, subtraction, and multiplication of integers. Now, let's understand Division of Integers. Division is the inverse operation of multiplication. This means that division 'undoes' multiplication. If we know that the product of two integers $a$ and $b$ is $c$ (i.e., $a \times b = c$), then dividing $c$ by $a$ gives $b$ (i.e., $c \div a = b$, provided $a \neq 0$), and dividing $c$ by $b$ gives $a$ (i.e., $c \div b = a$, provided $b \neq 0$). Division helps us split a quantity into equal parts or determine how many times one quantity is contained within another.


Rules for Division of Integers

Just like multiplication, the sign of the quotient (the result of division) depends on the signs of the integers being divided (the dividend and the divisor). The sign rules for division are directly related to the sign rules for multiplication because of the inverse relationship between the two operations.

Let $a$ and $b$ be non-zero integers.

1. Division of two positive integers

The quotient of two positive integers is a positive integer. This is the same as division of whole numbers.

$ (+) \div (+) = (+) $

Example: $(+10) \div (+2)$. Since $(+2) \times (+5) = +10$, then $(+10) \div (+2) = +5$, or simply $5$.

Example: $24 \div 6 = 4$.

2. Division of two negative integers

The quotient of two negative integers is a positive integer. To find the quotient, divide their absolute values.

$ (-) \div (-) = (+) $

Example: $(-10) \div (-2)$. We need a number that, when multiplied by $-2$, gives $-10$. We know $(-2) \times (+5) = -10$. So, the quotient is $+5$, or $5$.

So, $(-10) \div (-2) = 5$.

Example: $(-36) \div (-4) = +(36 \div 4) = 9$ (Since $(-4) \times 9 = -36$).

3. Division of one positive and one negative integer (or vice-versa)

The quotient of a positive integer and a negative integer (in either order) is always a negative integer. To find the quotient, divide their absolute values and place a negative sign before the result.

$ (+) \div (-) = (-) $

$ (-) \div (+) = (-) $

Example 1: $(+10) \div (-2)$. We need a number that, when multiplied by $-2$, gives $+10$. We know $(-2) \times (-5) = 10$. So, the quotient is $-5$.

So, $(+10) \div (-2) = -5$.

Example 2: $(-10) \div (+2)$. We need a number that, when multiplied by $+2$, gives $-10$. We know $(+2) \times (-5) = -10$. So, the quotient is $-5$.

So, $(-10) \div (+2) = -5$.

Example 3: $45 \div (-9) = -(45 \div 9) = -5$ (Since $(-9) \times (-5) = 45$).

Example 4: $(-28) \div 7 = -(28 \div 7) = -4$ (Since $7 \times (-4) = -28$).

Summary of Sign Rules for Division:

The sign rules for division are the same as those for multiplication:

Dividend Sign Divisor Sign Quotient Sign
Positive (+) Positive (+) Positive (+)
Negative (-) Negative (-) Positive (+)
Positive (+) Negative (-) Negative (-)
Negative (-) Positive (+) Negative (-)

In short: If the dividend and divisor have the **same sign**, the quotient is **positive**. If they have **different signs**, the quotient is **negative**.


Properties of Division of Integers

While multiplication of integers has many properties like closure, commutativity, and associativity, division of integers does not hold these properties in general.

1. Closure Property

The set of integers is not closed under division. This means that when you divide one integer by another integer, the result is not always an integer.

Example: $5 \div 2 = \frac{5}{2} = 2.5$. This is a decimal number, which is not an integer.

Example: $(-7) \div 3 = -\frac{7}{3}$. This is a fraction, which is not an integer.

The result of dividing two integers is a rational number. It will be an integer only if the dividend is perfectly divisible by the divisor (i.e., the remainder is zero).

2. Commutative Property

Division of integers is not commutative. Changing the order of the integers in a division problem generally changes the result.

In mathematical terms: For integers $a$ and $b$ ($b \neq 0, a \neq b$), $a \div b \neq b \div a$.

Example:

Let $a = -8$ and $b = 4$.

$a \div b = (-8) \div 4 = -2$.

$b \div a = 4 \div (-8) = \frac{4}{-8} = -\frac{1}{2}$.

Since $-2 \neq -\frac{1}{2}$, division is not commutative for integers.

3. Associative Property

Division of integers is not associative. The way you group integers when performing multiple divisions affects the result.

In mathematical terms: For integers $a, b, c$ ($b \neq 0, c \neq 0$), $(a \div b) \div c \neq a \div (b \div c)$ generally.

Example:

Let $a = -16$, $b = 4$, $c = -2$.

Calculate the Left Hand Side (LHS): $(a \div b) \div c$

$(a \div b) \div c = ((-16) \div 4) \div (-2)$

First, calculate inside the parenthesis: $(-16) \div 4$. (Negative $\div$ Positive $=$ Negative). $(-16) \div 4 = -4$.

Now, divide the result by $c$: $(-4) \div (-2)$. (Negative $\div$ Negative $=$ Positive). $(-4) \div (-2) = 2$.

So, LHS $= 2$.

Calculate the Right Hand Side (RHS): $a \div (b \div c)$

$a \div (b \div c) = (-16) \div (4 \div (-2))$

First, calculate inside the parenthesis: $4 \div (-2)$. (Positive $\div$ Negative $=$ Negative). $4 \div (-2) = -2$.

Now, divide $a$ by the result: $(-16) \div (-2)$. (Negative $\div$ Negative $=$ Positive). $(-16) \div (-2) = 8$.

So, RHS $= 8$.

Since LHS ($2$) is not equal to RHS ($8$), division is not associative for integers.

4. Property of Zero in Division

Zero has specific properties in division:

(a) Division of zero by any non-zero integer is zero.

If '$a$' is any non-zero integer ($a \neq 0$), then $0 \div a = 0$. This is because $a \times 0 = 0$.

Example: $0 \div 5 = 0$. $0 \div (-3) = 0$. $0 \div 100 = 0$.

(b) Division of any integer by zero is undefined.

Dividing any integer by $0$ is not defined in mathematics. This is because there is no number that, when multiplied by 0, gives a non-zero result. Also, if we were to define $a \div 0 = b$, it would imply $b \times 0 = a$. If $a \neq 0$, this is impossible. If $a=0$, then $b \times 0 = 0$, which is true for any value of $b$, so the result is not a unique number.

If '$a$' is any integer, $a \div 0$ is undefined.

Example: $7 \div 0$ is undefined. $(-4) \div 0$ is undefined.

5. Property of One in Division

One also has specific properties in division:

(a) Any integer divided by 1 gives the integer itself. This is the multiplicative identity property in reverse.

If '$a$' is any integer, then $a \div 1 = a$.

Example: $8 \div 1 = 8$. $(-5) \div 1 = -5$. $0 \div 1 = 0$.

(b) Any non-zero integer divided by itself gives 1.

If '$a$' is any non-zero integer ($a \neq 0$), then $a \div a = 1$. This is consistent with the rule that dividing two numbers with the same sign gives a positive result.

Example: $8 \div 8 = 1$. $(-5) \div (-5) = 1$.

(c) Any non-zero integer divided by -1 gives its additive inverse.

If '$a$' is any non-zero integer ($a \neq 0$), then $a \div (-1) = -a$. This is consistent with the rule that dividing two numbers with different signs gives a negative result.

Example: $8 \div (-1) = -8$ (additive inverse of 8). $(-5) \div (-1) = 5$ (additive inverse of -5).


Example 1. Evaluate: (a) $(-30) \div 10$ (b) $(-36) \div (-9)$ (c) $13 \div [(-2) + 1]$

Answer:

(a) Evaluate $(-30) \div 10$.

We are dividing a negative integer ($-30$) by a positive integer ($10$). According to the sign rules for division, a negative divided by a positive is negative.

Now, divide their absolute values: $30 \div 10 = 3$.

Assign the negative sign to the result: $-3$.

So, $(-30) \div 10 = -3$.


(b) Evaluate $(-36) \div (-9)$.

We are dividing a negative integer ($-36$) by a negative integer ($-9$). According to the sign rules for division, a negative divided by a negative is positive.

Now, divide their absolute values: $36 \div 9 = 4$.

Assign the positive sign to the result: $+4$ or $4$.

So, $(-36) \div (-9) = 4$.


(c) Evaluate $13 \div [(-2) + 1]$.

When there are operations within brackets, we perform the operations inside the brackets first.

First, evaluate the expression inside the bracket: $(-2) + 1$.

This is the addition of a negative integer ($-2$) and a positive integer ($1$). (Rule 3 for addition: $|-2|=2, |1|=1$, difference $2-1=1$, sign of -2). $(-2) + 1 = -1$.

Now substitute this result back into the original expression:

The expression becomes: $13 \div (-1)$.

We are dividing a positive integer ($13$) by a negative integer ($-1$). According to the sign rules, a positive divided by a negative is negative.

Now, divide their absolute values: $13 \div 1 = 13$.

Assign the negative sign to the result: $-13$.

So, $13 \div [(-2) + 1] = 13 \div (-1) = -13$.

Example 2. Verify that $a \div (b+c) \neq (a \div b) + (a \div c)$ for the values $a = 12, b = -4, c = 2$.

Answer:

Given values: $a = 12, b = -4, c = 2$.

We need to verify if the equality $a \div (b+c) = (a \div b) + (a \div c)$ is false for these values (i.e., the statement $a \div (b+c) \neq (a \div b) + (a \div c)$ is true).

Evaluate LHS (Left Hand Side):

LHS $= a \div (b+c)$

Substitute the given values:

$= 12 \div ((-4) + 2)$

First, calculate the sum inside the parenthesis: $(-4) + 2$. (Rule 3 for addition: $|-4|=4, |2|=2$, difference $4-2=2$, sign of -4). $(-4) + 2 = -2$.

Now, perform the division: $12 \div (-2)$. (Rule 3 for division: Positive $\div$ Negative $=$ Negative). $12 \div 2 = 6$. So, $12 \div (-2) = -6$.

So, LHS $= -6$.

Evaluate RHS (Right Hand Side):

RHS $= (a \div b) + (a \div c)$

Substitute the given values:

$= (12 \div (-4)) + (12 \div 2)$

First, calculate the division in the first parenthesis: $12 \div (-4)$. (Rule 3 for division: Positive $\div$ Negative $=$ Negative). $12 \div 4 = 3$. So, $12 \div (-4) = -3$.

Next, calculate the division in the second parenthesis: $12 \div 2$. (Rule 1 for division: Positive $\div$ Positive $=$ Positive). $12 \div 2 = 6$. So, $12 \div 2 = 6$.

Now, perform the addition of the results: $(-3) + 6$. (Rule 3 for addition: $|-3|=3, |6|=6$, difference $6-3=3$, sign of 6). $(-3) + 6 = 3$.

So, RHS $= 3$.

Compare the values of LHS and RHS:

LHS $= -6$

RHS $= 3$

Since LHS $\neq$ RHS ($-6 \neq 3$), the property $a \div (b+c) = (a \div b) + (a \div c)$ is indeed false for the given values.

This verification confirms that division is not distributive over addition for integers.



Order of Performing Operations

In mathematics, expressions can sometimes involve multiple operations, such as addition, subtraction, multiplication, division, and even brackets. When you have an expression with more than one operation, the order in which you perform these operations is crucial to get the correct answer. If you don't follow a specific order, you might get a different result each time, which would be confusing! To ensure consistency and accuracy, we follow a standard rule for the order of operations. This rule is commonly remembered by the acronym BODMAS (or sometimes PEMDAS in other countries).


The BODMAS Rule

The acronym BODMAS tells us the sequence in which operations should be performed in a mathematical expression:

The operations at the same level of precedence (like Division and Multiplication, or Addition and Subtraction) should be performed from left to right as they appear in the expression.

Types of Brackets and Order of Simplification:

If an expression contains multiple types of brackets, there's a specific order in which they should be simplified, starting from the innermost bracket and moving outwards:

  1. Vinculum or Bar ($ \overline{\phantom{aa}} $): This is a line drawn over a part of the expression. It's treated as the innermost grouping symbol and should be simplified first if present. Example: $5 \times \overline{4-2} = 5 \times 2 = 10$.
  2. Parentheses or Round Brackets ($ ( ) $): These are the next brackets to be simplified after any vinculum.
  3. Curly Brackets or Braces ($ \{ \} $): These are simplified after round brackets.
  4. Square Brackets or Box Brackets ($ [ ] $): These are the outermost brackets and are simplified last.

The order of removing brackets is: Vinculum $\to$ Parentheses $\to$ Curly Brackets $\to$ Square Brackets.


Examples using BODMAS Rule

Example 1. Simplify: $25 - 5 \times 2 + \{15 - (8 - 3)\}$.

Answer:

Given expression: $25 - 5 \times 2 + \{15 - (8 - 3)\}$.

Apply the BODMAS rule step-by-step:

Step 1: Brackets (Innermost first)

The innermost bracket is the round bracket $(8 - 3)$.

$(8 - 3) = 5 $

Substitute this value back into the expression:

$25 - 5 \times 2 + \{15 - 5\}$.

Next, solve the curly bracket $\{15 - 5\}$.

$\{15 - 5\} = 10 $

Substitute this value back into the expression:

$25 - 5 \times 2 + 10$. (All brackets are removed).

Step 2: Orders (None in this expression)

Step 3 & 4: Division and Multiplication (from left to right)

There is one multiplication operation: $5 \times 2$.

$5 \times 2 = 10 $

Substitute this value back into the expression:

$25 - 10 + 10$. (All multiplications/divisions are done).

Step 5 & 6: Addition and Subtraction (from left to right)

Perform operations from left to right. The first operation is subtraction $25 - 10$.

$25 - 10 = 15 $

Substitute this value back:

$15 + 10$.

The next operation is addition $15 + 10$.

$15 + 10 = 25 $

All operations are done.

Therefore, the simplified value of the expression is $25$.

Example 2. Simplify: $70 - [10 + \{ 20 - ( 30 \div 3 - 4 ) \}]$.

Answer:

Given expression: $70 - [10 + \{ 20 - ( 30 \div 3 - 4 ) \}]$.

Apply the BODMAS rule step-by-step:

Step 1: Brackets (Innermost first)

The innermost bracket is the round bracket $(30 \div 3 - 4)$. Inside this bracket, follow BODMAS again (Division before Subtraction).

First, perform the division inside the round bracket: $30 \div 3$.

$30 \div 3 = 10 $

The round bracket becomes $(10 - 4)$.

Now, perform the subtraction inside the round bracket: $10 - 4$.

$10 - 4 = 6 $

Substitute this value back into the expression. The round bracket is removed.

$70 - [10 + \{ 20 - 6 \}]$.

Next, solve the curly bracket $\{ 20 - 6 \}$. (Only subtraction inside).

$\{ 20 - 6 \} = 14 $

Substitute this value back. The curly bracket is removed.

$70 - [10 + 14]$.

Finally, solve the square bracket $[10 + 14]$. (Only addition inside).

$[10 + 14] = 24 $

Substitute this value back. The square bracket is removed.

$70 - 24$. (All brackets are removed).

Steps 2, 3, 4: Orders, Division, Multiplication (None in the remaining expression)

Steps 5 & 6: Addition and Subtraction (from left to right)

There is only one operation left: subtraction $70 - 24$.

$70 - 24 = 46 $

All operations are done.

Therefore, the simplified value of the expression is $46$.

Example 3. An elevator descends into a mine shaft at the rate of 6 metres per minute. If the descent starts from 10 m above the ground level, how long will it take to reach -350 m?

Answer:

Let the ground level be represented by 0 metres.

The elevator starts its descent from 10 m above the ground level. We can represent this position as $+10$ m.

The elevator needs to reach a depth of 350 m below the ground level. We represent this position as $-350$ m.

The total distance the elevator needs to descend is the difference between its starting point and its ending point on the vertical number line (with ground level as 0).

Total distance to descend = Starting position - Final position

Total distance to descend $= (+10 \text{ m}) - (-350 \text{ m})$

Using the rule for subtraction of integers ($a - (-b) = a + b$):

Total distance to descend $= 10 \text{ m} + 350 \text{ m} = 360 \text{ m}$.

The rate at which the elevator descends is given as 6 metres per minute.

To find the time taken, we divide the total distance to be covered by the rate of descent.

$\text{Time taken} = \frac{\text{Total distance to descend}}{\text{Rate of descent}}$

Substitute the values:

$\text{Time taken} = \frac{360 \text{ metres}}{6 \text{ metres/minute}}$

Perform the division of the numerical values and include the units:

$\text{Time taken} = 60 \text{ minutes}$.

Since 60 minutes is equal to 1 hour, the time taken is 1 hour.

Therefore, it will take 60 minutes or 1 hour for the elevator to reach -350 m.